(X+2)^2+(3x-1)^2=5x(2x+1)

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Solution for (X+2)^2+(3x-1)^2=5x(2x+1) equation: 



(X+2)^2+(3X-1)^2=5X(2X+1)

We move all terms to the left:

(X+2)^2+(3X-1)^2-(5X(2X+1))=0



We calculate terms in parentheses: -(5X(2X+1)), so:

5X(2X+1)

We multiply parentheses

10X^2+5X

Back to the equation:

-(10X^2+5X)



We get rid of parentheses

-10X^2+(X+2)^2+(3X-1)^2-5X=0

We add all the numbers together, and all the variables

-10X^2-5X+(X+2)^2+(3X-1)^2=0

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